If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2+x-5120=0
a = 1; b = 1; c = -5120;
Δ = b2-4ac
Δ = 12-4·1·(-5120)
Δ = 20481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{20481}}{2*1}=\frac{-1-\sqrt{20481}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{20481}}{2*1}=\frac{-1+\sqrt{20481}}{2} $
| x^2+2x-5120=0 | | (x+1/4)^2=(√31/16)^2 | | 2x-7/3x+2=4 | | (x-4)^2=168 | | 3(p-3)=4p | | -8+4m=23 | | 7+15x=100 | | -8+4m=m | | -34+9y+9=(4y-2)-4 | | 4(c-2)+9=6+c-5 | | (2/x)-5/3=12/x | | 4y^+20y=0 | | 5u^-10u=0 | | 5(1-x)+3(1+x)÷1-2x=8 | | (2x+4)/4=8 | | (x)/4-2=5 | | 9+(x)/2=14 | | 50=10√10^2-y^2 | | x-1/7x-14=x-3/7x-26 | | 4(x-5)+2=3x+7 | | 15/7-3x=4/3 | | 9p/14+19=2p | | s-11*5=20 | | 4(3s+10)=76 | | 2(m+4)=10 | | 4(3+x)=8-4x | | 1500÷x-1500÷x+250=1 | | (x+4)/4=(2x+1)/6 | | 50-3x=9 | | 5(a+3)=4(a+3) | | 4s2-100=0 | | (-3(x+1))/5=x-7 |